sin130.tan60 ÷cos540.tan230.sin400

Answer 1

sin130° = sin 50°
tan60° = √3
cos540° = cos180 = -1
tan230° = tan50

sin400= sin40

sin130.tan60 ÷cos540.tan230.sin400
= (sin50°)(√3)/(-1) (tan50)(sin40)
= -√3sin50 (sin50/cos50)(sin40)
= -√3 sin40° sin^2 50° / cos50°

I see nothing special from here.
Were there brackets of sorts ?

Answer 2

I think it was

sin130.tan60 ÷(cos540.tan230.sin400)
= (sin50 √3)/(-1 * sin50/cos50 * sin40)
= -√3 cos50/sin40

But since cos50 = sin40, the result is just

-√3