Sin theta,cos theta,tan theta are in g.p. prove that cot^6 theta-cot^2 theta =1

Answer 1

since the ratio is constant,

cosθ/sinθ = tanθ/cosθ
cotθ = tanθ/cosθ
cot^2θ = secθ
cot^4θ = sec^2θ
cot^4θ = 1+tan^2θ
cot^6θ = cot^2θ+1
cot^6θ-cot^2θ = 1

Answer 2

I cannot able to understand the clear answer

Answer 3

Sorry I understand it so thanks

Answer 4

I can understand clearly thanks u so much