sinθ = 8/17 in QII means that
cosθ = -15/17
sin2θ = 2sinθcosθ = 2(8/17)(-15/17)
cos2θ = cos^2θ - sin^2θ = (15/16)^2 - (8/17)^2
tan2θ is of course, sin2θ/cos2θ
sin theta = 8/17 and theta is in the second quadrant. Find sin(2theta),cos(2theta),tan(2theta) exactly
sin(2theta)
cos(2theta)
tan(2theta)
sin(2theta) would it be 2 x (8/17)
cos(2theta) would be 2 x (15/17)
tan(2theta) would be 2 x (8/17 divided by 15/17)
is this correct? I tried punching that into my homework for as an attempt and it comes back incorrect. Maybe I am not writing the exact answers correctly?
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