sin(θ − ϕ); tan(θ) = 5/12

Question

,
θ in Quadrant III,
sin(ϕ) = − square root 10 over 10
ϕ in Quadrant IV

Please help last one

Answer 1

sin(θ) = -5/13 , cos(θ) = -12/13

cos(ϕ) = .3√10

sin(θ − ϕ) = sin(θ)cos(ϕ) -
... cos(θ)sin(ϕ)