sin(tan^-1(-7/3)) How do i evaluate this? answer has to be exact with no decimals.. calculators not allowed either..

Answer 1

If you know the tangent to be 7/-3, you know the sin: -3/(sqrt(49+9) right?

Answer 2

The tangent is negative in II or IV

so sin(tan^-1(-7/3)
= 7/√58 or -7/√58