Funny - you and Ruth need to compare notes ...
in QI
sinθ = 5/13
cosθ = 12/13
in QII
sinϕ = 1/√5
cosϕ = -2/√5
sin(θ+ϕ) = (5/13)(-2/√5)+(12/13)(1/√5) = 2/(13√5)
sin(θ + ϕ);
sin(θ) = 5/13 θ in Quadrant I,
cos(ϕ) = − 2root 5 over 5 ϕ in Quadrant II
please give final answer this is bc i have a lot of trouble simplifying the final answer thank you
1 answer
1 answer