sin(πcosx)-cos(πsinx)=0

Question

then find sin2x
step plz

Answer 1

since cos(z) = sin(π/2 - z)
sin(πcosx)-cos(πsinx)=0
sin(πcosx) = cos(πsinx)
sin(πcosx) = sin(π/2 - πsinx)
so,
π cosx = π/2 - πsinx
π(cosx+sinx) = π/2
cosx+six = 1/2

You can probably take it from there, eh?