(sin/cos)/ ( 1/cos - 1) = I'm stumped

Answer 1

(sin/cos)(1-cos)/cos
sin(1 - cos)/cos^2
I see nothing special about this.
could it be:
(sin/cos) [1/(cos-1)] ???
then
(sin/cos) [1/(cos-1)][(cos+1)/cos+1)]

(sin/cos)(cos+1)/(cos^2-1)

-(sin/cos)(cos+1)/sin^2
- (cos+1)/sin cos

Answer 2

The actual question goes :
make the left the same as the right:
left side:
tan/sec - 1 = right side
sin/1-cos

Answer 3

I bet you mean

tan/(sec - 1) = sin/(1-cos)
PARENTHESES ARE VITAL
otherwise you are just wasting time
(sin/cos)/[(1/cos)-cos/cos] = sin/(1-cos)

sin/(1-cos) = sin/(1-cos)

Answer 4

Thanks Damon.