sin(((cos^-1)(3/5))-((sin^-1)(5/13)))

Question

help and explain please

Answer 1

let A = cos^-1 (3/5)
then cos A = 3/5, and sinA = 4/5 (using the 3-4-5 triangle)

let B = sin^-1 (5/13)
sin B = 5/13 and cosB = 12/13

so sin(((cos^-1)(3/5))-((sin^-1)(5/13)))
= sin(A - B)
= sinAcosB - cosAsinB
= (4/5)(12/13) - (3/5)(5/13)
= 48/64 - 15/64
= 33/65

Answer 2

thanks a lot

it helped

(: