sin^2è + 2sinè +1 =0
5 answers
that e symbol is suppose to be theta
treat sine theta as x, and it get's really easy!
x^2+2x+1=0
Factor,
(x+1)(x+1)=0
now replace sine theta:
(sine theta + 1)^2=0
theta=sine^-1(0)
theta=0
Cheers,
Houdini
x^2+2x+1=0
Factor,
(x+1)(x+1)=0
now replace sine theta:
(sine theta + 1)^2=0
theta=sine^-1(0)
theta=0
Cheers,
Houdini
I again disagree with Houdini
He is ok to the end of
(sinØ + 1)^2 = 0
sinØ + 1 = 0
sinØ = -1
Ø = 270° or 3π/2 radians
Houdini's answer does not satisfy the equation.
He is ok to the end of
(sinØ + 1)^2 = 0
sinØ + 1 = 0
sinØ = -1
Ø = 270° or 3π/2 radians
Houdini's answer does not satisfy the equation.
Reiny's right -.-
tan pi/5=