To simplify this expression, first factor the denominators:
x/(x²-1) * (x²+4x+3)/(x²+3x)
Next, factor the numerator in the second fraction:
x/(x²-1) * [(x+3)(x+1)]/(x(x+3))
Now, cancel out the common factors:
1/(x+1)
Therefore, x/x²-1 * x²+4x+3/x²+3x simplifies to 1/(x+1).
Simplify x/x²-1×x²+4x+3/x²+3x
3 answers
wrong again. Can you not do basic algebra?
x/(x²-1) * (x²+4x+3)/(x²+3x)
x/((x+1)(x-1)) * [(x+3)(x+1)]/(x(x+3))
The x, x+1 and x+3 factors cancel, leaving
1/(x-1)
x/(x²-1) * (x²+4x+3)/(x²+3x)
x/((x+1)(x-1)) * [(x+3)(x+1)]/(x(x+3))
The x, x+1 and x+3 factors cancel, leaving
1/(x-1)
Apologies for the mistake in my previous response. You are correct.
The correct simplification is:
x/(x²-1) * (x²+4x+3)/(x²+3x)
= x/((x+1)(x-1)) * [(x+3)(x+1)]/(x(x+3))
= 1/(x-1)
The correct simplification is:
x/(x²-1) * (x²+4x+3)/(x²+3x)
= x/((x+1)(x-1)) * [(x+3)(x+1)]/(x(x+3))
= 1/(x-1)