Since A∩(BC) = A∩B ∪ A∩C,
your first step is
(X ∪ Y ∪ Z)∩X ∪ (X ∪ Y ∪ Z)∩(Y∩Z)
and now break down each of those similarly. Just review your basic set properties. Recall that X∪X = X∩X = X
Simplify(X U Y U Z) n (X U (Y n Z))
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