Answer to #2:
m^4n^2.
I subtracted the m's and subtracted the m's. It's one of the exponent rules.
I have NO idea how to do the first question.
SImplify:
(x - 9/x) / (1 + x/3)
and (m^-1 + n^-1) / (m^-3 + n^-3)
I have no idea what to do
4 answers
you cant do that, Miley, the m's and n's are separated by an addition sign, so you cant use the quotient of powers rule
oh okay sry, at least i tried
for the first one, just multiply them using FOIL
to get
x + (x^2)/3 - 9/x - 3
for the second, use the rule for negative exponents to write
(1/m + 1/n)/(1/m^3 + 1/n^3)
finding common denominators and simplifying both top and bottom I got
(m+n)/mn / (m^3 + n^3)/m^3n^3
= (m+n)/mn * (m^3n^3)/(m^3 + n^3)
= m^2n^2(m+n) / (m^3 + n^3)
the bottom factors to (m+n)(m^2 - mn + n^2)
so we have
m^2n^2(m+n) / ((m+n)(m^2 - mn + n^2))
= m^2n^2 / (m^2 - mn + n^2)
to get
x + (x^2)/3 - 9/x - 3
for the second, use the rule for negative exponents to write
(1/m + 1/n)/(1/m^3 + 1/n^3)
finding common denominators and simplifying both top and bottom I got
(m+n)/mn / (m^3 + n^3)/m^3n^3
= (m+n)/mn * (m^3n^3)/(m^3 + n^3)
= m^2n^2(m+n) / (m^3 + n^3)
the bottom factors to (m+n)(m^2 - mn + n^2)
so we have
m^2n^2(m+n) / ((m+n)(m^2 - mn + n^2))
= m^2n^2 / (m^2 - mn + n^2)
3 answers