To simplify the sum \(\frac{7y+9}{y-9} + \frac{8y+5}{y-9}\), we can combine the fractions since they have a common denominator:
\[ \frac{7y+9 + 8y+5}{y-9} = \frac{(7y + 8y) + (9 + 5)}{y-9} \]
Combine the like terms in the numerator:
\[ 7y + 8y = 15y \] \[ 9 + 5 = 14 \]
So, we get:
\[ \frac{15y + 14}{y - 9} \]
Now let's state any restrictions on the variable \(y\). The denominator \(y - 9\) cannot be zero. Therefore, we have:
\[ y - 9 \neq 0 \implies y \neq 9 \]
This means we cannot allow \(y\) to equal 9.
The final answers are:
-
\(\frac{15y + 14}{y - 9}\) for \(y \neq 9\).
-
\(\frac{15y + 14}{y - 9}\) for all values of \(y\), assuming \(y \neq 9\).
Thus, it simplifies to:
- \(\frac{15y + 14}{y - 9}\) for \(y \neq 9\).
- \(\frac{15y + 14}{y - 9}\) for all values of \(y\) with the restriction \(y \neq 9\).