To simplify the polynomial expression \((xy - 2)(x^2 + 1)\), we will use the distributive property (also known as the FOIL method for binomials). Here's how to do it:
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Distribute \(xy\) to both terms in \( (x^2 + 1) \): \[ xy \cdot x^2 = x^3y \] \[ xy \cdot 1 = xy \]
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Distribute \(-2\) to both terms in \( (x^2 + 1) \): \[ -2 \cdot x^2 = -2x^2 \] \[ -2 \cdot 1 = -2 \]
Now we combine all the results: \[ x^3y + xy - 2x^2 - 2 \]
Next, we can rearrange this expression into standard form, typically ordered by decreasing powers of \(x\): \[ x^3y - 2x^2 + xy - 2 \]
Finally, we fill in the blanks for your formatted answer:
- Coefficient of \(x^3y\): \(1\)
- Coefficient of \(x^2\): \(-2\)
- Coefficient of \(xy\): \(1\)
- Constant term: \(-2\)
So, the final answer is: \(1\) \(x^3y\) + \(-2\) \(x^2\) + \(1\) \(xy\) + \(-2\)