write it as:
x^3(x^2-1)^(-5/8) + 2x(x^2-1)^3/8
common factor is x(x^2 - 1)^(-5/8)
so we get
=x(x^2 - 1)^(-5/8) [ x^2 + 2(x^2 - 1)]
= x(x^2 - 1)^(-5/8) (3x^2 - 2)
or
= x(3x^2 - 2)/(x(x^2 - 1)^(5/8) )
Simplify the following into a single expression
x^3/(x^2-1)^5/8 + 2x(x^2-1)^3/8
3 answers
Thanks and thanks for the help on how to write it out on the computer.
You are welcome