I'll do one. You just need to remember that
log(ab) = log(a) + log(b)
log(a^n) n log(a)
So, (c) can be done as follows:
log4(64^k)
= log4(4^3^k)
= log4(4^(3k))
= 3k
since log_b(b) = 1 for any b
I think you have garbled (d).
Try using some parentheses to clarify, or try typing it in at wolframalpha.com to see how it interprets it.
It will recognize log_3(x) as log3x
Simplify the following expressions. Your answers must be exact and in simplest form.
(a) log8(8^−5x−10)=
(b) 12^log12(−5+7q)=
(c) log4(64^k)=
(d) 3^3log3(10−10log3^3)=
2 answers
ok thx!