Tell you what -- why don't you simplify them and we'll check your answers.
To get started on (a)
√3-i = 2cis -π/6
so, (√3-i)^4 = 16cis -2π/3
now just convert that back to rectangular values.
Simplify the following expressions by using trigonometric form and De Moivre's theorem
a. (√3-i)^4
b. (-4+4i√3)^5
c.(2+3i)^4
d. (4-i)^6
4 answers
but i don't get the first one
You need to review the methods of expressing complex numbers as a+bi and r cisθ. Surely your text has a discussion of the topic.
Also, a simple google on "complex numbers polar" will turn up may explanations and examples.
√3-i can be plotted as the point (√3,-1) in the x-y plane.
Now, measuring from the x-axis, that point is at an angle of -π/6, and is 2 units from the origin. Hence the polar form.
Also, a simple google on "complex numbers polar" will turn up may explanations and examples.
√3-i can be plotted as the point (√3,-1) in the x-y plane.
Now, measuring from the x-axis, that point is at an angle of -π/6, and is 2 units from the origin. Hence the polar form.
What do I do next after that?
1 answer