To simplify the expression
\[ \frac{x + 6}{x^2 + 3x} - \frac{5}{x^2 + x - 6} \]
we will first factor the denominators.
- Factor the denominators:
- \(x^2 + 3x = x(x + 3)\)
- \(x^2 + x - 6\) factors to \((x - 2)(x + 3)\).
Now we rewrite the expression with the factored denominators:
\[ \frac{x + 6}{x(x + 3)} - \frac{5}{(x - 2)(x + 3)} \]
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Find a common denominator: The common denominator of \(x(x + 3)\) and \((x - 2)(x + 3)\) is \(x(x - 2)(x + 3)\).
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Rewrite each fraction with the common denominator: \[ \frac{(x + 6)(x - 2)}{x(x - 2)(x + 3)} - \frac{5x}{x(x - 2)(x + 3)} \]
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Combine the fractions: \[ \frac{(x + 6)(x - 2) - 5x}{x(x - 2)(x + 3)} \]
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Expand the numerator: \[ (x + 6)(x - 2) = x^2 - 2x + 6x - 12 = x^2 + 4x - 12 \] So now the expression is: \[ \frac{x^2 + 4x - 12 - 5x}{x(x - 2)(x + 3)} = \frac{x^2 - x - 12}{x(x - 2)(x + 3)} \]
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Factor the numerator \(x^2 - x - 12\): This can be factored to \((x - 4)(x + 3)\), so we have: \[ \frac{(x - 4)(x + 3)}{x(x - 2)(x + 3)} \]
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Cancel the common factors: The \((x + 3)\) cancels out, giving us: \[ \frac{x - 4}{x(x - 2)} \]
Thus, the final simplified expression is: \[ \frac{x - 4}{x^2 - 2x} \]
So the correct answer among your provided options is:
\(\frac{x - 4}{x^2 - 2x}\)