Simplify the expression
8t⁵•8t⁵
11 answers
64t¹⁰
Can u explain please ?
Certainly!
When you multiply two powers with the same base, you can simply add the exponents. In this case, the base is 8t.
So, you can rewrite the expression as:
8t⁵ • 8t⁵ = (8t)⁵ • (8t)⁵
And then, you can multiply the coefficients and add the exponents:
(8t)⁵ • (8t)⁵ = 8•8 • t⁵ • t⁵ = 64t¹⁰
When you multiply two powers with the same base, you can simply add the exponents. In this case, the base is 8t.
So, you can rewrite the expression as:
8t⁵ • 8t⁵ = (8t)⁵ • (8t)⁵
And then, you can multiply the coefficients and add the exponents:
(8t)⁵ • (8t)⁵ = 8•8 • t⁵ • t⁵ = 64t¹⁰
5k²(-6k²-2k+6)
To simplify this expression, you need to apply the distributive property of multiplication.
You'll multiply 5k² by each term inside the parentheses, and then combine like terms.
5k²•(-6k²-2k+6) = (-30k⁴ - 10k³ + 30k²)
You'll multiply 5k² by each term inside the parentheses, and then combine like terms.
5k²•(-6k²-2k+6) = (-30k⁴ - 10k³ + 30k²)
(2k+1)(k-4)
To multiply these two binomials, you can use the FOIL method, which stands for:
First: multiply the first terms in each binomial
Outer: multiply the outer terms in each binomial
Inner: multiply the inner terms in each binomial
Last: multiply the last terms in each binomial
Then, you can combine any like terms.
So, applying the FOIL method:
(2k+1)(k-4) = (2k)(k) + (2k)(-4) + (1)(k) + (1)(-4)
= 2k² - 8k + k - 4
= 2k² - 7k - 4
So, the simplified expression is 2k² - 7k - 4.
First: multiply the first terms in each binomial
Outer: multiply the outer terms in each binomial
Inner: multiply the inner terms in each binomial
Last: multiply the last terms in each binomial
Then, you can combine any like terms.
So, applying the FOIL method:
(2k+1)(k-4) = (2k)(k) + (2k)(-4) + (1)(k) + (1)(-4)
= 2k² - 8k + k - 4
= 2k² - 7k - 4
So, the simplified expression is 2k² - 7k - 4.
(-y+4)(2y-1)
Using the FOIL method, we get:
(-y+4)(2y-1) = (-y)(2y) + (-y)(-1) + (4)(2y) + (4)(-1)
Simplifying this expression, we get:
-2y² + y + 8y - 4
Combining like terms, we get:
-2y² + 9y - 4
So the final simplified expression is -2y² + 9y - 4.
(-y+4)(2y-1) = (-y)(2y) + (-y)(-1) + (4)(2y) + (4)(-1)
Simplifying this expression, we get:
-2y² + y + 8y - 4
Combining like terms, we get:
-2y² + 9y - 4
So the final simplified expression is -2y² + 9y - 4.
Look at the given triangles.
They are 4x+2 7x+7 5x-4 and ×+3 2x-5 x+7
Write an expression in simplest forn for the perimeter of each triangle
Write another expression in simplest form that shows the difference between the perimeter of the larger triangle and the perimeter of the smaller triangle
Find the perimeter for each triangle when x=3
They are 4x+2 7x+7 5x-4 and ×+3 2x-5 x+7
Write an expression in simplest forn for the perimeter of each triangle
Write another expression in simplest form that shows the difference between the perimeter of the larger triangle and the perimeter of the smaller triangle
Find the perimeter for each triangle when x=3
We don't have the image or the correct number of values given to solve this problem. Can you please provide the complete problem statement?
15 answers