f (2 + h ) = ( 2 + h ) ^ 2 - 3 * ( 2 + h )
f ( 2 ) = 2 ^ 2 - 3 * 2 = 4 - 6 = - 2
[ f ( 2 + h ) − f ( 2 ) ] / h =
[ ( 2 + h ) ^ 2 - 3 * ( 2 + h ) - ( - 2 ) ] =
[ 2 ^ 2 + 2 * 2 * h + h ^ 2 - 3 * 2 - 3 * h + 2 ] / h =
[ 4 + 4 h + h ^ 2 - 6 - 3 h + 2 ] / h =
( h ^ 2 + h ) / h = h * ( h + 1 ) / h = h + 1
Simplify the difference quotient
[f(2 + h) − f(2)]/h ; if h ≠ 0.
f(x) = x2 − 3x
I keep getting the answer wrong. I must be messing up my steps...Please Help
3 answers
[ f ( 2 + h ) − f ( 2 ) ] / h =
[ ( 2 + h ) ^ 2 - 3 * ( 2 + h ) - ( - 2 ) ] / h =
[ 2 ^ 2 + 2 * 2 * h + h ^ 2 - 3 * 2 - 3 * h + 2 ] / h =
[ 4 + 4 h + h ^ 2 - 6 - 3 h + 2 ] / h =
( h ^ 2 + h ) / h = h * ( h + 1 ) / h = h + 1
[ ( 2 + h ) ^ 2 - 3 * ( 2 + h ) - ( - 2 ) ] / h =
[ 2 ^ 2 + 2 * 2 * h + h ^ 2 - 3 * 2 - 3 * h + 2 ] / h =
[ 4 + 4 h + h ^ 2 - 6 - 3 h + 2 ] / h =
( h ^ 2 + h ) / h = h * ( h + 1 ) / h = h + 1
OH! thanks. I just messed up a tiny calculation haha. It's such a messy question..