Simplify the 4 to the power of 13 ÷ 3 to the power of −5 answer is not 243

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To simplify \( 4^{13} \div 3^{-5} \), we can rewrite the expression using the property of exponents \( a^{-b} = \frac{1}{a^{b}} \).

Starting with the expression:

\[ 4^{13} \div 3^{-5} \]

This can be rewritten as:

\[ 4^{13} \times 3^{5} \]

Now, we simply compute the values separately.

First, let's compute \( 4^{13} \). We know that \( 4 = 2^2 \), so:

\[ 4^{13} = (2^2)^{13} = 2^{26} \]

Next, we have \( 3^{5} \).

Putting it all together, we have:

\[ 4^{13} \times 3^{5} = 2^{26} \times 3^{5} \]

Thus, the expression simplifies to:

\[ 2^{26} \times 3^{5} \]

This is the simplified form of \( 4^{13} \div 3^{-5} \).

The numerical value can be calculated, but the expression itself is effectively simplified as \( 2^{26} \times 3^{5} \).

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