Simplify, stating any restrictions on the variables: x+1/2x^2-7x+6 - x-3/2x^2-x-3

Answer 1

assuming the usual carelessness with parentheses, I get
(x+1)/(2x^2-7x+6) - (x-3)/(2x^2-x-3)
= (x+1)/((x-2)(2x-3)) - (x-3)/((x+1)(2x-3))
Since division by zero is undefined, x=2, 3/2, -1 are excluded from the domain.
Combining over a common denominator yields
= ((x+1)^2 - (x-3)(x-2))/((x-2)(x+1)(2x-3))
= (7x-5)/((x-2)(x+1)(2x-3))
The three excluded values are still evident.

Answer 2

@ooblect are there any restrictions?

Answer 3

@oobleck

Answer 4

yes. I said which real numbers are excluded from the domain.
Uhhh .. those are restrictions, right?