an (2a-4)=2(a-2) or -2(2-a) which will cancel out your 2-a,
then do the same for the 2a+4, and this should give you your answer
Simplify. State the nonpermissible values.
4a^2-1/4a^2-16*2-a/2a-1
This is what I did to try and solve it out:
(2a+1)(2a-1)/(2a+4)(2a-4)*2-a/(2a-1)
I cancelled out the (2a-1)'s and don't get how to solve.
I'm supposed to get the answer :
-2a-1/4(a+2)
But I don't get how to get that^.
4 answers
Thanks so much =)
I read that as
(4a^2-1)/(4a^2-16) * (2-a)/(2a-1) , my brackets are necessary
= (2a+1)(2a-1)/( 4(a+2)(a-2) * (2-a)/(2a-1)
the (2-a)/(a-2) are opposite, they will give you the -1
so..
= -(2a+1)/(4(a+2)) , again you have to use brackets to write it on here.
(4a^2-1)/(4a^2-16) * (2-a)/(2a-1) , my brackets are necessary
= (2a+1)(2a-1)/( 4(a+2)(a-2) * (2-a)/(2a-1)
the (2-a)/(a-2) are opposite, they will give you the -1
so..
= -(2a+1)/(4(a+2)) , again you have to use brackets to write it on here.
Thanks Reiny =) But I to get everything clear, the 2-a and the a-2 cancel right? After I cancel those I am left with (2a+1) as the numerator:S Sorry I am just confused. Also did you factor out the 2a+4 and 2a-4 to get 4(a+2)(a-2)? Could you please explain step by step?
4 answers