To simplify the expression \(\frac{9x^2 - 32x + 10}{x - 5}\), we first need to factor the numerator \(9x^2 - 32x + 10\).
Step 1: Factor the quadratic \(9x^2 - 32x + 10\)
We need to find two numbers that multiply to \(9 \times 10 = 90\) and add to \(-32\). Those numbers are \(-30\) and \(-2\).
We can rewrite the middle term: \[9x^2 - 30x - 2x + 10\]
Next, we factor by grouping: \[(9x^2 - 30x) + (-2x + 10)\] \[= 3x(3x - 10) - 2(3x - 10)\] \[= (3x - 10)(3x - 1)\]
Step 2: Rewrite the expression
Now we can rewrite the original expression: \[\frac{(3x - 10)(3x - 1)}{x - 5}\]
Step 3: Check if we can simplify further
The terms \(3x - 10\) and \(x - 5\) don't factor further to allow for cancellation.
Final form
Thus, the expression is: \[\frac{(3x - 10)(3x - 1)}{x - 5}\]
Fill In The Blanks
Now we can fill in the blanks:
- Blank space 1: \(3x - 10\)
- Blank space 5: \(3x - 1\)
- Blank space 6: \(x - 5\)
To summarize:
- Blank space 1: \(3x - 10\)
- Blank space 5: \(3x - 1\)
- Blank space 6: \(x - 5\)