Simplify. Remove all the perfect squares from the root (sqrt) 20x^8

1 answer

To simplify \(\sqrt{20x^8}\), we first break it down into its components:

  1. Factor 20: \[ 20 = 4 \times 5 \] Here, \(4\) is a perfect square.

  2. Analyze \(x^8\): \[ x^8 = (x^4)^2 \] This means \(x^8\) is also a perfect square.

Now, we can rewrite \(\sqrt{20x^8}\) using these factors:

\[ \sqrt{20x^8} = \sqrt{4 \times 5 \times (x^4)^2} \]

Next, we can separate the square root of the perfect squares from the square root of the non-perfect squares:

\[ \sqrt{20x^8} = \sqrt{4} \times \sqrt{5} \times \sqrt{(x^4)^2} \]

Calculating the square roots of the perfect squares:

\[ \sqrt{4} = 2 \quad \text{and} \quad \sqrt{(x^4)^2} = x^4 \]

Putting it all together, we have:

\[ \sqrt{20x^8} = 2 \times x^4 \times \sqrt{5} \]

Thus, the simplified expression is:

\[ 2x^4 \sqrt{5} \]

Therefore, the final answer is:

\[ \boxed{2x^4 \sqrt{5}} \]

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