Simplify.

Remove all perfect squares from inside the square root. Assume
\[a\] is positive.
\[\sqrt{27a}=\]

1 answer

To simplify \(\sqrt{27a}\), we start by breaking down \(27\) into its prime factors:

\[ 27 = 3^3. \]

Thus, we can rewrite \(27a\) as follows:

\[ 27a = 3^3 a. \]

Now, we can express the square root as:

\[ \sqrt{27a} = \sqrt{3^3 \cdot a}. \]

Next, we can separate the square root using the property \(\sqrt{x \cdot y} = \sqrt{x} \cdot \sqrt{y}\):

\[ \sqrt{27a} = \sqrt{3^3} \cdot \sqrt{a}. \]

We know that \(\sqrt{3^3} = \sqrt{9 \cdot 3} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3}\). Therefore, we can substitute this back into our expression:

\[ \sqrt{27a} = 3\sqrt{3} \cdot \sqrt{a}. \]

This simplifies further to:

\[ \sqrt{27a} = 3\sqrt{3a}. \]

Thus, the simplified form of \(\sqrt{27a}\) is:

\[ \boxed{3\sqrt{3a}}. \]

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