Simplify logx(x/4)+3logx(2/5)-log21(2/25)

Answer 1

is that last term log base 21?

Answer 2

whatever - we can start with

log_x(x/4) = log_x(x) - log_x(4) = 1-log_x(4)

So, assuming all logs to the same base (x), we can make it

1+log(1/4 * 8/125 * 25/2) = 1-2log5

I suspect multiple typos