since the denominators are the same, just add numerators. Just as
2/5 + 1/5 = 3/5,
-4x/(x+7) - 8/(x+7) = (-4x-8)/(x+7)
So, C
-2/(x+3) - 4/(x-5)
= [-2(x-5) - 4(x+3)]/[(x+3)(x-5)
= (-2x+10-4X-12)/[(x+3)(x-5)
= (-6x-2)/[(x+3)(x-5)
So, A
Simplify into one fraction. -4x/x+7-8/x+7
A. -4x+8/x+7
B. X-8/x
C. -4x-8/x+7
D. X+7/-4x**
Simplify into one fraction. -2/x+3-4/x-5
A. -6x-2/(x+3)(x-5)
B. 6(x-1)/(x+3)(x-5)
C. -6/(x+3)(x-5) ***
D. 2/(x+3)(x-5)
1 answer