Please don't capitalize your variables, it makes it hard to read them.
(-x + y - 2(-2y)(x - y) )/( (x-y)^2 + (x+y)^2 )
= (-x + y + 4xy - 4y^2)/(x^2 - 2xy + y^2 + x^2 + 2xy + y^2)
= ( x(4y - 1) - y(4x - 1) )/( 2(x^2 + y^2) )
= (4x-1)(x-y) / (2(x^2 + y^2) )
for the second, I don't see much happening
you could separate the fraction into
(x^3 + 4x^2y + 4xy^2)/(x+2y) + (2xy - 6y^2)/(x+2y)
= x(x^2 + 4xy + 4y^2)/(x+2y) + 2y(x - 3y)/(x-2y)
= x(x-2y)^2 / (x-2y) + 2y(x-3y)/(x-2y
= x(x-2y) + 2y(x-3y)/(x-2y)
if that second-last term had been 3xy we could have done more.
Was there a typo ?
Simplify each of the following expressions into simplest terms.
a) {[-X+Y+(-2)*(-2Y)*[X-Y]}/[(X-Y)^2+(X+Y)^2]
b)
(X^3+4X^2Y+4XY^2+2XY-6Y^2)/(X+2Y)
4 answers
no no typo the equation is
(x^3+4x^2y+4xy^2+2xy-6y^2)/(x+2y)
sorry about the caps on my first post
(x^3+4x^2y+4xy^2+2xy-6y^2)/(x+2y)
sorry about the caps on my first post
i did however seem to have made a typo on the first equation the right one is
{[-x+y+(-2y)]*[x-y]}/[(x-y)^2+(x+y)^2]
{[-x+y+(-2y)]*[x-y]}/[(x-y)^2+(x+y)^2]
If no typo in the second, then my answer stands as is
for the first, follow my steps with your corrected expression. There should be only minor changes.
for the first, follow my steps with your corrected expression. There should be only minor changes.