assuming the usual carelessness with parentheses, I get
(2x+10)/(x+5) = 2(x+5)/(x+5) = 2
(x^2-25)/(3x-15) = (x+5)(x-5) / 3(x-5) = (x+5)/3
(x^2+4x)/(x^2-9x) = x(x+4) / x(x-9) = (x+4)/(x-9)
(n^2+7n+10)/(n^2+2n-15)
= (n+2)(n+5) / (n-3)(n+5)
= (n+2)/(n-3)
Simplify each expression.
1. 2x + 10/x+5
2.x^2 - 25/3x - 15
3. x^2 + 4x/x^2 - 9x
4. n^2 + 7n + 10/ n^2 + 2n - 15
Please explain how to do these I don't understand!
1 answer
1 answer