sin^-1 x is the angle Ø so that sinØ = x or x/1
so you have a right-angled triangle with opposite side x and hypotenuse 1
then y^2 + x^2 = 1
y = √(1 - x^2)
and cos(sin^-1 x)
= cosØ
= √(1 - x^2)
test for some value of x
let's say x = .1234
then sin^-1 (.1234) = 7.08836...°
cos 7.08836..° = .992357..
and √(1 - .1234^2) = .992357..
My answer has a high probability of being correct
simplify:
cos(sin^-1(x))
Can someone please show a step by step of how to do this.
1 answer
1 answer