3x^2-21x+36 GCF: 3, so divide the whole thing by 3.
x^2-7x+12
(What two #s add up to -7 and multiplied equal 12? 3 and 4)
[x^2-4x] - [3x+12]
x(x-4) - 3(x-4)
(x-4)(x-3)=0
x-4= 4 x-3= 3 Answer X=3 and 4
*simplify by combining like terms, if possible. then, remove the GCF and factor fully.
2x^2-21x+36+x^2
=3x^2-21x+36
...i'm not sure what to do after that, could you help and show the steps please
2 answers
I thought it said, factor fully.
You had
3x^2 - 21x + 36 , which is correct
= 3(x^2 - 7x + 12)
= 3(x-4)(x-3)
nothing was said about "solving" the equation, since there was no equation.
You had
3x^2 - 21x + 36 , which is correct
= 3(x^2 - 7x + 12)
= 3(x-4)(x-3)
nothing was said about "solving" the equation, since there was no equation.