( 2 + sin^2/cos^2)(1/cos^2) = 1 + y^2
(2/cos^2 + sin^2 /cos^4) = 1 + y^2
y^2 = (2 cos^2 + sin^2)/cos^4 - 1
y=+/- sqrt[ (2 cos^2 + sin^2)/cos^4 - 1 ]
Simplify and write the trigonometric expression in terms of sine and cosine:
((2+tan^2 x)(sec^2 x))-1 = (f(x))^2
f(x)= ???
3 answers
that is not right according the program
( 2 + sin^2/cos^2)(1/cos^2) = 1 + y^2
(2 cos^2 + sin^2) /cos^4 = 1 + y^2
y^2 = (2 cos^2 + sin^2)/cos^4 - 1
y=+/- sqrt[ (2 cos^2 + sin^2)/cos^4 - 1 ]
well you could write it this way
y = +/- sqrt[ ( cos^2 +1)/cos^4 - 1]
(2 cos^2 + sin^2) /cos^4 = 1 + y^2
y^2 = (2 cos^2 + sin^2)/cos^4 - 1
y=+/- sqrt[ (2 cos^2 + sin^2)/cos^4 - 1 ]
well you could write it this way
y = +/- sqrt[ ( cos^2 +1)/cos^4 - 1]
2 answers