I will assume you meant:
(9^90-9^89) / (3^2)^89
then
= 9^89(9 - 1)/(9^89)
= 8
Simplify
9^90-9^89 / (3^2)^89
Its 9^90 right?
4 answers
I do not understand what you did. Can you please explain? Sorry for the inconvenience.
I used a common factor of 9^89
suppose I had x^90 - x^89
wouldn't x^89 be the highest common factor and we have
x^89(x - 1)
so at the top I had:
9^90 - 9^89
9^89(9^1 - 1) = 9^89 (8)
at the bottom the 3^2 is 9 , so
(3^2)^89
= 9^89 , which canceled the 9^89 at the top , leaving 8
suppose I had x^90 - x^89
wouldn't x^89 be the highest common factor and we have
x^89(x - 1)
so at the top I had:
9^90 - 9^89
9^89(9^1 - 1) = 9^89 (8)
at the bottom the 3^2 is 9 , so
(3^2)^89
= 9^89 , which canceled the 9^89 at the top , leaving 8
Thank you
3 answers