Simplify 8x^8 - 8x^2 -28x/4x

Answer 1

To simplify the expression \( \frac{8x^8 - 8x^2 - 28x}{4x} \), we can start by factoring out the common term in the numerator.

1. We can factor out \( 4x \) from the numerator:

\[ 8x^8 - 8x^2 - 28x = 4x(2x^7 - 2x - 7) \]

2. Now, we can rewrite the entire expression:

\[ \frac{8x^8 - 8x^2 - 28x}{4x} = \frac{4x(2x^7 - 2x - 7)}{4x} \]

3. Notice that \( 4x \) in the numerator and denominator cancels out:

\[ = 2x^7 - 2x - 7 \quad \text{(assuming } x \neq 0\text{)} \]

So the simplified expression is:

\[ \boxed{2x^7 - 2x - 7} \]