Asked by Mike Tyson
Simplify 80x3y2 (1 point)
2
○ 4x²y²√5x
4xy√5x
○ 5x2 y2√4x
5xy√4x
2
○ 4x²y²√5x
4xy√5x
○ 5x2 y2√4x
5xy√4x
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To simplify the expression \( 80x^3y^2 \), we can factor it down.
1. **Factor out the coefficients and variables:**
- \( 80 = 16 \times 5 \)
- \( x^3 = x^2 \cdot x \)
- \( y^2 = y^2 \) (it stays the same)
Thus, we can write:
\[
80x^3y^2 = 16 \cdot 5 \cdot x^2 \cdot x \cdot y^2
\]
2. **Grouping components:**
If we want to express in terms of the choices provided, we can also breakdown \( 80x^3y^2 \):
#### Options given:
- **\( 4x^2y^2\sqrt{5x} \)**
- **\( 4xy\sqrt{5x} \)**
- **\( 5x^2y^2\sqrt{4x} \)**
- **\( 5xy\sqrt{4x} \)**
#### Approaching the square elements:
We don't have a direct simplification that matches any of the provided forms without additional modifications. However, let's see how close we can get to one of these forms via square roots.
\[
80x^3y^2 = 16 \cdot 5 \cdot x^2 \cdot x \cdot y^2 = (4x^2y^2) \times (20x)
\]
Then express \( 20x \) specifically as \( 4\sqrt{5x} \times 5 \).
3. **Calculation with square roots:**
Let's see if we can manipulate and simplify with roots.
Using \( 20 = 4\sqrt{5x} \):
\[
80x^3y^2 = 4x^2y^2 \cdot (5\cdot 4\sqrt{5x}) = 4x^2y^2\sqrt{20x}
\]
This does not fit any provided choices exactly either.
### Conclusion
From these steps, it's clear that the simplifications provided do not precisely match the expression \( 80x^3y^2 \) simplifications in various presented forms.
However, the expression \( 5x^2y^2\sqrt{4x} \) could imply a multiple.
So in conclusion, if you have options as choices to select, examine the definitions closely to check values; however, the best answer from given choices appears to be: **\( 4x^2y^2\sqrt{5x} \)** based on proximity and transformations but would still yield differing input from what was observed. It really depends on how you are looking or plotting directly against input!!
1. **Factor out the coefficients and variables:**
- \( 80 = 16 \times 5 \)
- \( x^3 = x^2 \cdot x \)
- \( y^2 = y^2 \) (it stays the same)
Thus, we can write:
\[
80x^3y^2 = 16 \cdot 5 \cdot x^2 \cdot x \cdot y^2
\]
2. **Grouping components:**
If we want to express in terms of the choices provided, we can also breakdown \( 80x^3y^2 \):
#### Options given:
- **\( 4x^2y^2\sqrt{5x} \)**
- **\( 4xy\sqrt{5x} \)**
- **\( 5x^2y^2\sqrt{4x} \)**
- **\( 5xy\sqrt{4x} \)**
#### Approaching the square elements:
We don't have a direct simplification that matches any of the provided forms without additional modifications. However, let's see how close we can get to one of these forms via square roots.
\[
80x^3y^2 = 16 \cdot 5 \cdot x^2 \cdot x \cdot y^2 = (4x^2y^2) \times (20x)
\]
Then express \( 20x \) specifically as \( 4\sqrt{5x} \times 5 \).
3. **Calculation with square roots:**
Let's see if we can manipulate and simplify with roots.
Using \( 20 = 4\sqrt{5x} \):
\[
80x^3y^2 = 4x^2y^2 \cdot (5\cdot 4\sqrt{5x}) = 4x^2y^2\sqrt{20x}
\]
This does not fit any provided choices exactly either.
### Conclusion
From these steps, it's clear that the simplifications provided do not precisely match the expression \( 80x^3y^2 \) simplifications in various presented forms.
However, the expression \( 5x^2y^2\sqrt{4x} \) could imply a multiple.
So in conclusion, if you have options as choices to select, examine the definitions closely to check values; however, the best answer from given choices appears to be: **\( 4x^2y^2\sqrt{5x} \)** based on proximity and transformations but would still yield differing input from what was observed. It really depends on how you are looking or plotting directly against input!!
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