Question

Simplify 
(5x+3)+(8x+1) 
(5x)+(8x)= 13x^2 
(5x)+(1)=5x 
(3)+(8x)=11x 
(3)+(1)=4 
=13x^2+5x+11x+4 
=13x^2+16x+4 
Is this right or wrong?

Simplify
(2t^2-3t)-(7t^2-5t) 
= (2t^2)-(7t^2)=-5t 
= (2t^2)-(-5t)= 7t 
=(-3t)-(7t^2)=-10t 
=(-3t)-(-5t)=2t 
=-5t+7t-10t+2t 
I am confused. Why are all my answers "t" and none of them are "t^2"?

Answer 1

You do not show any multiplications or divisions in your given problems. All you can do is collect like terms.

(5x+3)+(8x+1)
is the same as
5x+3+8x+1
which is
13 x + 4
===========================
similarly
(2t^2-3t)-(7t^2-5t)

= 2 t^2 - 3 t - 7 t^2 + 5 t

Note that +5 t due to double - sign -( -5 ) = +5

= -5 t^2 + 2 t

Answer 2

Oh okay. So since there is a adding or subtracting sign with brackets, all you do is collect like terms? Okay. So it is not distributive property

Answer 3

no, not distributive property of multiplication


If the question were

(5x+3)(8x+1) no plus sign, so TIMES

then you could say
5x (8x+1)
+
3 (8x+1)

That would be distributive property.