To simplify \(4x + 8x\), you can combine like terms. Both terms have \(x\) as a variable.
So,
\[ 4x + 8x = (4 + 8)x = 12x \]
The simplified expression is \(12x\).
Among the response options given, the correct one is:
12x (12 x).
Responses
12x2
12 x squared
4x + 8
4 x plus 8
12x
12 x
4 + 8x
9 answers
To simplify \(4x + 8x\), you can combine like terms. Both terms have \(x\) as a variable.
So,
\[ 4x + 8x = (4 + 8)x = 12x \]
The simplified expression is \(12x\).
Among the response options given, the correct one is:
12x (12 x).
To simplify \(9g − 7h − 6g + 2h\), we can combine like terms.
Combine the \(g\) terms: \[ 9g - 6g = (9 - 6)g = 3g \]
Combine the \(h\) terms: \[ -7h + 2h = (-7 + 2)h = -5h \]
Putting it all together, we have: \[ 3g - 5h \]
Among the response options given, the correct one is:
3g − 5h.
To simplify \(2a − 4b + 7 + 8a + 6b − 2\), we can combine like terms step by step.
Combine the \(a\) terms: \[ 2a + 8a = 10a \]
Combine the \(b\) terms: \[ -4b + 6b = 2b \]
Combine the constant terms: \[ 7 - 2 = 5 \]
Putting it all together, we have: \[ 10a + 2b + 5 \]
Among the response options given, the correct one is:
10a + 2b + 5.
To simplify \(\frac{3}{7}x + \frac{2}{7}x\), you can combine the like terms since they both have \(x\) as a common factor.
Combine the coefficients: \[ \frac{3}{7} + \frac{2}{7} = \frac{3 + 2}{7} = \frac{5}{7} \]
Since both terms also include \(x\), we can write: \[ \frac{5}{7}x \]
Among the response options given, the correct one is:
\(\frac{5}{7}x\) (5/7x).
To simplify the expression \( \frac{6}{7}c - \frac{5}{9}d - \frac{1}{2}c + \frac{1}{3}d \), we need to combine like terms.
First, let’s group the \(c\) terms and the \(d\) terms separately:
For the \(c\) terms:
Converting each term: \[ \frac{6}{7}c = \frac{12}{14}c \quad \text{(since } 6 \times 2 = 12\text{)} \] \[ -\frac{1}{2}c = -\frac{7}{14}c \quad \text{(since } 1 \times 7 = 7\text{)} \] Now combine: \[ \frac{12}{14}c - \frac{7}{14}c = \frac{12 - 7}{14}c = \frac{5}{14}c \]
For the \(d\) terms:
Converting: \[ \frac{1}{3}d = \frac{3}{9}d \quad \text{(since } 1 \times 3 = 3\text{)} \] Now combine: \[ -\frac{5}{9}d + \frac{3}{9}d = \frac{-5 + 3}{9}d = -\frac{2}{9}d \]
Putting it all together, we have: \[ \frac{5}{14}c - \frac{2}{9}d \]
Among the response options given, the correct one is:
\(\frac{5}{14}c - \frac{2}{9}d\) (5/14c − 2/9d).