Simplify: (2x-3y4)3(x3 + y)0 / (4xy-2)3

Answer 1

(2x-3y^4)^3 (x^3 + y)^0 / (4xy-2)^3
(x^3+y)^0 = 1, so that just leaves

(2x-3y)^3 / (4xy-2)^3
you could expand both of those polynomials, but to what advantage, I don't know.
or, make it

((2x-3y)/(4xy-2))^3

Answer 2

sorry

((2x-3y^4)/(4xy-2))^3