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simplify

122-3 x 4^2+√4-3

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To simplify the expression \( 122 - 3 \times 4^2 + \sqrt{4} - 3 \), let's follow the order of operations (PEMDAS/BODMAS).

  1. Calculate \( 4^2 \): \[ 4^2 = 16 \]

  2. Calculate \( 3 \times 16 \): \[ 3 \times 16 = 48 \]

  3. Calculate \( \sqrt{4} \): \[ \sqrt{4} = 2 \]

Now, substitute these values back into the expression: \[ 122 - 48 + 2 - 3 \]

  1. Now perform the operations from left to right:

    • First, calculate \( 122 - 48 \): \[ 122 - 48 = 74 \]

    • Next, add \( 2 \): \[ 74 + 2 = 76 \]

    • Finally, subtract \( 3 \): \[ 76 - 3 = 73 \]

Thus, the simplified result of the expression is: \[ \boxed{73} \]