since the demominator is (x+1)(x+5) both x ≠ both -1 and -5
when x = -5, you have 0/0, which is also undefined.
for the 2nd problem. whenever the denominator is zero, division is undefined, so x ≠ -4
when x = 1, you just have 0/5 = 0, which is perfectly fine
Simplify
1... x+5/x^2+6x+5
Answer... 1/x+1 where x is not equal to -1, -5 (Is this correct? Or is it just -1? Or just 5?)
2... x^2+3x-4/x+4
Answer... x-1 where x is not equal to 1 (or -4...?)
2 answers
Thx