simplfey the product
(4y-7)(2y^2-8y+1)
3 answers
8y^3 - 32y^2 + 4y - 14y^2 + 56y - 7
come again?
Sure! Let's simplify the product of (4y-7)(2y^2-8y+1) step by step:
First, multiply 4y by each term in the second parenthesis:
4y * 2y^2 = 8y^3
4y * (-8y) = -32y^2
4y * 1 = 4y
Next, multiply -7 by each term in the second parenthesis:
-7 * 2y^2 = -14y^2
-7 * (-8y) = 56y
-7 * 1 = -7
Combining all the terms gives us:
8y^3 - 32y^2 + 4y - 14y^2 + 56y - 7
Now, simplifying by combining like terms:
8y^3 - 32y^2 - 14y^2 + 4y + 56y - 7
8y^3 - 46y^2 + 60y - 7
So, the simplified product is 8y^3 - 46y^2 + 60y - 7.
First, multiply 4y by each term in the second parenthesis:
4y * 2y^2 = 8y^3
4y * (-8y) = -32y^2
4y * 1 = 4y
Next, multiply -7 by each term in the second parenthesis:
-7 * 2y^2 = -14y^2
-7 * (-8y) = 56y
-7 * 1 = -7
Combining all the terms gives us:
8y^3 - 32y^2 + 4y - 14y^2 + 56y - 7
Now, simplifying by combining like terms:
8y^3 - 32y^2 - 14y^2 + 4y + 56y - 7
8y^3 - 46y^2 + 60y - 7
So, the simplified product is 8y^3 - 46y^2 + 60y - 7.
1 answer