Let's analyze Simon's recorded time of 15.36 seconds.
- The digits in Simon's measurement are:
- Ones place: 5
- Tens place: 1
- Tenths place: 3
- Hundredths place: 6
According to the information given:
-
Trey's measurement has the same digits in the ones and tens place as Simon's measurement. This means Trey's ones digit will be 5 and tens digit will be 1.
- So, Trey's measurement starts with "15."
-
The digit in the tenths place of Trey's measurement has a value that is 10 times the value of the digit in the hundredths place of Simon's measurement. The digit in the hundredths place for Simon's measurement is 6. Therefore:
- 10 times the digit in the hundredths place (6) is \(10 \times 6 = 60\).
- Trey's tenths digit must be equal to 60.
However, it seems unrealistic because a digit must be a single digit (0-9).
Let's check the options again while recalling the properties found above:
- The digits in the ones (5) and tens (1) places of Simon's measurement are consistent with our interpretation.
- Following the rule where the tenths digit must have a value that is 10 times that of the hundredths place in Simon's measurement, it's likely that there was an intent to find a more straightforward relationship.
This means we should just consider reasonable tenths that align properly, since the use of 10 times gives an impractical expectation for the format of how time works in tenths and hundredths.
Thus let's consider the provided options:
- 15.6 seconds: This uses 5 (ones) and 1 (tens) but does not match Simon's measurements in hundredths (needs tenths of 6).
- 14.6 seconds: This replaces the tens digit with 4, so it doesn't satisfy our condition.
- 15.46 seconds: Holds 5 (ones) and 1 (tens) and corresponds to a tenths of 4, and clearly doesn't represent being 10 times anything.
- 14.36 seconds: Falls into the same trap of having mixed digits.
Thus, when mindful of our requisite condition that tenths were to consider closely against standard timekeeping formats as logically they could point toward:
Let's affirm Tenths as truly needing to read higher but corresponding effectively. The digit in hundredths must emulate the tenths effectively.
Therefore, none present match, but if we had to adjust the tenths directly for ease: Tentatively, 15.46 can work sensibly regarding keeping decimal placement. Therefore:
Trey's final recording for Harry's time would be 15.46 seconds.