Similar question to http://www.jiskha.com/display.cgi?id=1474753951
"If that 22.33g sample of calcium chloride was dissolved in 1000.0g of water, with both substances originally at 25.0C, what would be the final temperature of the solution be? Assume no loss of heat to the surroundings and that the entire solution has a specific heat capacity of 4.184J/gC."
CaCl2(s) -> Ca(aq) + 2Cl(aq) ΔH_rxn = +198.0 KJ
*The amount of heat that would be absorbed for 22.33g of CaCl2 is +40.2KJ.
Is the heat absorbed is related to the question above? From that other question forum, the person mentioned "176kj=1000*4.18*deltaTemp". Where did they get the 176KJ? I'm very confused on this question, thank you.
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