Silver bromide, AgBr,

Question

decomposes into silver (Ag)
solid and bromine, (Br ) liquid
at room temperature. Which
ratio of silver to bromine is in
the products of the reaction?
(1 point)
2
4:3
2:1
2:3
1:3

Answer 1

The decomposition of silver bromide (AgBr) can be represented by the equation:

\[ 2 , \text{AgBr (s)} \rightarrow 2 , \text{Ag (s)} + \text{Br}_2 , \text{(l)} \]

In this reaction, 2 moles of silver bromide decompose to produce 2 moles of solid silver (Ag) and 1 mole of liquid bromine (Br₂).

To find the ratio of silver (Ag) to bromine (Br), we look at the amounts produced:

• For every 2 moles of Ag produced, 1 mole of Br₂ is produced.

Thus, the ratio of silver to bromine is:

\[ \text{Ratio of Ag to Br} = 2:1 \]

Therefore, the correct answer is:

2:1

Answer 2

The left side of a chemical
reaction is shown.
Mg(OH)2 + 2HNO3 →
Which type of reaction will the
reactants undergo?
(1 point)
single displacement
synthesis
double displacement
decomposition

Answer 3

The reaction shown is:

\[ \text{Mg(OH)}_2 + 2\text{HNO}_3 \rightarrow \]

This can be classified as a double displacement reaction (also known as a double replacement or metathesis reaction).

In a double displacement reaction, the cations and anions of the reactants exchange places to form new products. In this case, magnesium hydroxide \((\text{Mg(OH)}_2)\) and nitric acid \((\text{HNO}_3)\) will exchange components to form new solutions.

So the correct answer is:

double displacement