This looks like a limiting reagent (LR) problem.
SiO2 + 2C ==> SiC + CO2
mols SiO2 = grams/molar mass = approx 50/60.1 = approx 0.0832
mols C = 50/12 = approx 0.0416
mols SiC formed using just SiO2 = 1:1; therefore, 0.0832.
mols SiC formed using just C = 0.0416 x 1/2 = 0.0208 so C is the limiting reagent and the amount of SiC formed is the SMALLER of the two possible answers.
grams SiC = mols SiC x molar mass SiC = ?
Silicon Carbide, SiC, is prepared by heating silicon dioxide in the presence of graphite. Carbon dioxide is the by-product of the reaction. How many grams of silicon carbide can be formed from the reaction of 50.0 grams fo graphite with 50.0 grams of silicon dioxide?
1 answer