The only way to compare 1.10g to 1.20 moles is to change one of them to grams/moles.
1.20moles F2=1.2*38=45.6 grams.
Heat= 18.9kJ * 45.6/1.10
SiH4(g) + 2 F2(g) SiF4(g) + 4 HF(g)
If 18.9 kJ are released when 1.10 g of F2 reacts with an excess of SiH4, what is the heat of the reaction when 1.20 moles of F2 react?
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