To estimate \( 52.75 \) using the graph of \( y = 5x \), you'll need to find the value of \( x \) such that \( y \) is approximately \( 52.75 \).
The equation \( y = 5x \) can be rearranged to solve for \( x \):
\[ x = \frac{y}{5} \]
Substituting \( y = 52.75 \):
\[ x = \frac{52.75}{5} = 10.55 \]
Now, looking for the best estimate of \( 52.75 \) from the provided options, we can quickly review them to see which value \( y \) corresponds to \( x = 10.55 \) using the equation:
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For \( x = 39 \): \[ y = 5 \cdot 39 = 195 \]
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For \( x = 75 \): \[ y = 5 \cdot 75 = 375 \]
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For \( x = 80 \): \[ y = 5 \cdot 80 = 400 \]
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For \( x = 100 \): \[ y = 5 \cdot 100 = 500 \]
None of the options directly correspond to \( 52.75 \) on the \( y \) scale when plugged into the equation \( y = 5x \). To match the original equation closely and estimate visually based on a graph, you might want to analyze where \( 5x \) crosses a value close to \( 52.75 \) (which is between \( 50 \) and \( 60 \)).
If the addition of \( 39, 75, 80, \) or \( 100 \) are available as points and given they won't correlate directly as to \( 52.75 \) but rather as to a nearby coordinate along the line, I suggest looking to the visual context. In graph evaluation, you would need an estimation method where you're more focused on the computer or visual lookup tables.
Often, people misinterpret the intentions of nearby values. In near calculations of \( y = 52.75 \):
- Choosing \( 80 \) gives \( 5x \rightarrow 400 \),
- Choosing \( 75 \) gives a higher error between \( \approx 375 \).
Given available values don't meet precisely but register against visualization, concluding on a suitable estimate pivots toward that \( y = 75 \) being less than any higher value which would fit beneath or near to 52.75 as well. Thus, the final choice while not accurately targeting \( y = 52.75 \) appears closest toward \( 39 \) loosely compared against variants.
Thus, the suggestion of the best estimate of \( y = 52.75 \) aligns to:
39.
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