To determine which points are part of the solution set for the inequality \( y \leq 25x + 1 \), we need to check each point to see if it satisfies the inequality.
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For the point \((-10, 6)\): \[ y \leq 25(-10) + 1 \ 6 \leq -250 + 1 \ 6 \leq -249 \quad \text{(False)} \]
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For the point \((10, 5.5)\): \[ y \leq 25(10) + 1 \ 5.5 \leq 250 + 1 \ 5.5 \leq 251 \quad \text{(True)} \]
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For the point \((10, 4)\): \[ y \leq 25(10) + 1 \ 4 \leq 250 + 1 \ 4 \leq 251 \quad \text{(True)} \]
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For the point \((10, 6)\): \[ y \leq 25(10) + 1 \ 6 \leq 250 + 1 \ 6 \leq 251 \quad \text{(True)} \]
Conclusion:
The points \((10, 5.5)\), \((10, 4)\), and \((10, 6)\) are part of the solution set for the inequality \( y \leq 25x + 1 \). The point \((-10, 6)\) is not part of the solution set.